Quarterback Joe Tarkenton can throw a football downfield at a speed of 60 feet per second. When releasing the ball, his arm is 6 feet above ground. The height of the ball after seconds is given by the function: h(t)=−16^2+60+6. What is the maximum height of the football?

If the ball is not caught, how many seconds will it take to reach the ground after being thrown?

A: maximum height=3.58 feet; time=62.25 seconds

B: maximum height=62.52 feet; time=3.58 seconds

C: maximum height=62.25 feet; time=3.85 seconds

D: maximum height=3.85 feet; time=62.52 seconds

C: maximum height=62.25 feet; time=3.85 seconds

Step-by-step explanation:

Vertex of a quadratic function:

Suppose we have a quadratic function in the following format:

It's vertex is the point

In which

Where

If a<0, the vertex is a maximum point, that is, the maximum value happens at , and it's value is .

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

.

This polynomial has roots such that , given by the following formulas:

In this question:

The height of the ball, after t seconds, is given by the following equation:

Which is a quadratic equation with

Maximum height:

Since a < 0, we can find the maximum value of the function. We have that:

The maximum height is of 62.25 feet.

Seconds to reach the ground:

Since time is a positive measure, 3.85 seconds.

The correct answer is given by option C.

step-by-step explanation:

you can add the two numbers and divide the result by 2. or you can find the gap between the two numbers and add half of this to the smaller number.

b

step-by-step explanation:

it have 5 sides and 5 identicle angle.the rest does not have the same property as b.

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