Identify the sets that contain 2 as an element. (Check all that apply.)Check All That Apply{2, 3, 4, 5, ...}{2, 3, 4, 5, ...}{0, 1, 4, 9, ...}{0, 1, 4, 9, ...}{ 2, {2} }{ 2, {2} }{ {2}, { {2} } }{ {2}, { {2} } }{ {2}, { 2, {2} } }{ {2}, { 2, {2} } }{ { {2} } }{ { {2} } }

Question:

Identify the sets that contain 2 as an element. (Check all that apply.)

Step-by-step explanation:

Required

For which of the options is 2 an element

The elements of this set starts from 2, then 3 and continues as thus.

Hence: 2 is an element

From the given elements in the above set, 2 is not listed.

Hence: 2 is not an element of this set

Here, 2 is listed as an element, 2 is also listed as a subset.

Since 2 is listed as an element, then 2 is an element of the set.

Here, 2 is listed as a subset of {2} and also as a subset of subset of {{2}}.

Since 2 is not listed as an element itself, then 2 is not an element of the set.

Here, 2 is listed as a subset of {2} and also as a subset of subset of {2,{2}}. This set only contains subsets, i.e. 2 is not listed as a direct element of the set.

Hence: 2 is not an element of the set

Here, 2 is listed as a subset of subset of {{2}}. This set only contains subsets, i.e. 2 is not listed as a direct element of the set.

Hence: 2 is not an element of the set

3/6   and 9/18

step-by-step explanation:

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.