Suppose that the weight of an newborn fawn is Uniformly distributed between 2.1 and 3.9 kg. Suppose that a newborn fawn is randomly selected. Round answers to 4 decimal places when possible. a. The mean of this distribution is
b. The standard deviation is
c. The probability that fawn will weigh exactly 2.6 kg is P(x = 2.6) =
d. The probability that a newborn fawn will be weigh between 2.3 and 3.5 is P(2.3 < x < 3.5) =
e. The probability that a newborn fawn will be weigh more than 3.16 is P(x > 3.16) =
f. P(x > 2.8 | x < 3.1) =
g. Find the 7th percentile.

at first, in 1635, the evening meetings had been just for women . .

what relationship between ideas is shown in the text above?

question 1 options:

location of events

similarity of events

timing of events

examples of an idea

step-by-step explanation:

a

step-by-step explanation:

strong negative correlation

answer: get a conversion sheet out i dont know the exact measurments

step-by-step explanation: divide the number of feet with the nu,ber of milrs and there your answer

c.

step-by-step explanation:

substitution for (0,1)

y=x^2+4x+1

1=0^2+4(x)0+1

1=0+4(x)0+1

1=4(x)0+1

1=0+1

1=1

substitution for (-3,-2)

y=x+1

-2=-3+1

-2=-2