Find the general solution:
y'-2y=t^2*e^2t

Lindsay used two points, (x,y; ) and (+2.82), to find the equation of the line, y = mx + b, that passes through the points. y2-y, first, she used the definition of slope and determined that the value of mis x, - . given this information, which expression must represent the value of b?

Evaluate 3(a + b + c)squared for a = 2, b = 3, and c = 4. a. 54 b. 243 c.729 add solution .

The graph of y x3 is translated so that the point (1. 1) is moved to (1, 4). what is the equation of the new graph?