In the spinner below, what is the probability of landing on 5? A.2/6
B.1/4
C.1/8
D.1/12

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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fdvs

step-by-step explanation: vsfdvsfvd