The population of bacteria in an experiment is increasing by 90% each
day. If there were 100 bacteria at the
beginning of the experiment, predict the
number of bacteria in 5 days.
First, complete the equation:
Future Amount = [?](1+[DU
what would the equation

Future amount = 100(1.9)^5 ;

2476

Step-by-step explanation:

P(t) = P0 * (1 + r)^t

P(t) = 100 * (1 + 90/100)^t#

P(t) = 100 * (1 + 0.9)^t

Therefore, the number of bacteria in 5 years :

P(5) = 100 * (1 + 0.9)^5

P(5) = 100 * (1.9)^5

P(5) = 100 * 24.76099

P(5) = 2476.099

P(5) = 2476 bacteria

P(10%

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.