The velocity of a ball thrown upward into the air is given by v(t)= -32t+96 where t is measured in seconds and velocity v in feet per second calculate the displacement of the ball between t=1 and t=4

The displac ment between t = 1 and t = 4 is 272 feet

Step-by-step explanation:

To get the displacement of the ball, we first need to get the equation for the position of the ball with respect to time.

We can do this by differentiating the velocity equation given:

v(t) = -32t +96

integrating between the limits of t = 1 and t = 4, we have

where t = 4.

s = 256 + (96) =352 feet

Where t = 1

s = 80

Displacement of the ball = 352 -80 = 272ft

The displac ment between t = 1 and t = 4 is 272 feet

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

452,489 to the nearest thousand is 452,000