For Quon's first 6 quizzes he had a mean score of 33 points. After his 7th quiz his mean score was 32 points. After the 8th quiz the mean was 34. What was the difference in scores between his 7th and 8th quizzes

Difference in scores between his 7th and 8th quizzes = 22

Step-by-step explanation:

Given: Mean score for first 6 quizzes is 33 points. After his 7th quiz his mean score was 32 points. After the 8th quiz the mean was 34.

To find: difference in scores between his 7th and 8th quizzes

Solution:

Mean scores = Total points scored in quizzes ÷ Number of quizzes

So,

Total points scored in quizzes = Mean scores × Number of quizzes

As mean score for first 6 quizzes is 33 points,

Total points scored in 6 quizzes = 6 × 33 = 198

As mean score for first 7 quizzes is 32 points,

Total points scored in 7 quizzes = 7 × 32 = 224

So,

7th score = Total points scored in 7 quizzes - Total points scored in 6 quizzes

               = 224 - 198

               = 26

As mean score for first 8 quizzes is 34 points,

Total points scored in 8 quizzes = 8 × 34 = 272

So,

8th score = Total points scored in 8 quizzes - Total points scored in 7 quizzes

               = 272 - 224

               = 48

Therefore,

Difference in scores between his 7th and 8th quizzes = 48 - 26

                                                                                          = 22

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.

hi how are you doing today, if you need just ask me.

step-by-step explanation: