Write a polynomial equation for a graph that passes through the point (-1, 60) and has three x-intercepts: (-4,0), (1, 0), and (3, 0)

Given:

A graph of a polynomial passes through the point (-1, 60) and has three x-intercepts: (-4,0), (1, 0), and (3, 0).

To find:

The equation of the polynomial.

Solution:

A polynomial is defined as:

Where, a is a constant and are the zeros of the polynomial.

The given polynomial has three x-intercepts (-4,0), (1, 0), and (3, 0). It means are the zeroes of the given polynomial and are the factors of the given polynomial.

So, the equation of the polynomial is:

          ...(i)

It passes through the point .

Divide both sides by 24.

Putting in (i), we get

Therefore, the equation of the given polynomial is .

true

step-by-step explanation:

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)