A circle with a radius of 1 in. is inscribed in a right triangle with legs of 3 in. and 4 in. If a point is randomly chosen within the triangle, what is the probability that the point is NOT also in the circle?​

P = (6-π)/6

Explanation:

Circle Area:

CA = 1²×π

CA ≈ π in²

Triangle Area:

TA = 3×4/2 = 6 in²

Probability:

P(point not in circle) = (6-π)/6 ≈ 0.48 ≈ 47.64%

32

step-by-step explanation:

these are your clues: 1. kim ran 18 races2. this was four fewer races than twice thenumber, notice it says twice the number, so you would do the equation 18x2-4; which equals the number 32.thus, 32 is your answer.