Write an equation of the ellipse with foci at (+-3, 0) and co-vertices at (0,+- 1). A.) x^2/10+y^2=1
B.) x^2+y^2/10=1
C.) x^2/10+y^2/9=1
D.) x^2/9+y^2=1​

step-by-step explanation:

assume that you have 3 different side lengths.   apply the pythagorean theorem here:   square each of the two shortest sides; call them a and b, so that their squares are a² and b².   also square the longest side, calling the result c².

now, if a² + b² = c² is true, the triangle is a right triangle; otherwise it is not a right triangle.