Find the truth set of each predicate. (If your answer is an interval, enter it using interval notation; otherwise enter it using set-roster notation.) (a) Predicate: 10 d is an integer, domain: Z (b) Predicate: 10 d is an integer, domain: Z+ (c) Predicate: 1 ≤ x2 ≤ 9, domain: R (d) Predicate: 1 ≤ x2 ≤ 9, domain: Z

10

step-by-step explanation:

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3

your answer would be 12