An Internet service provider sampled 540 customers and found that 55 of them experienced an interruption in their service during the previous month. Construct a 95% confidence interval for the proportion of all customers who have experienced a service interruption. (0.080, 0.123) (0.873, 0.924) (0.076, 0.127) (0.102, 0.898)

a 95% confidence interval for the proportion of all customers who have experienced a service interruption: (0.076, 0.127).

Step-by-step explanation:

Let p be the population proportion of all customers who have experienced a service interruption.

Confidence interval for p:, where = sample proportion, n= sample size, z* = critical z-value.

Given: n = 540

z* = 1.96

The required confidence interval:

Hence, a 95% confidence interval for the proportion of all customers who have experienced a service interruption: (0.076, 0.127).

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step-by-step explanation:

distance formula is d=√(x2-x1)^2   +   (y2-y1)^2

answer: 7270

step-by-step explanation: