Find the center and radius of the circle defined by the equation given below. x ^ 2 + 2x + y ^ 2 + 10y = 15?

Step-by-step explanation:

Remark

Complete the square for x and for y.

complete for x

x^2 + 2x + (2/2)^2

(x + 1)^2

Complete square for y

y^2 + 10y + (10/2)^2

(y + 5)^2

Now put these two together

(x + 1)^2 + (y + 5)^2 = 15 + (10/2)^2 + (2/2)^2

(x + 1)^2 + (y + 5)^2 = 15 + 25 + 1

(x + 1)^2 + (y + 5)^2 = 41

Answer

Center: (-1,-5)

radius: (sqrt(41) = 6.403

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?