Which term of the sequence –3, 1, 5, 9, 13, … is 65? Alisha solved the question as shown below.

an = 65

a1 = –3

d = –3 – 1 = –4

65 = –3 + (n–1)(–4)

65 = –3 –4n + 4

65 = 1 – 4n

65–1 = 4n

n = 64 ÷ 4

n = 16

So, the 16th term of the sequence is 65.

What is the error in the computation? Find the correct answer.

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Astudent must have an average on five test that is greater than it equal to 80% but less than 90% to receive a final grade of b. devon's greades on the first four test were 78% 62% 91% and 80% what range if grades on the fifth test would give him a b in the course? ( assuming the highest grade is 100%)

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