If 27 ×32 = 3x×2y;find the values of x and y​

Step-by-step explanation:

hello :

27 ×32 = 3x×2y

means : 27 ×32 = 6xy

xy= (27 ×32)/6

xy = 144

but : 144 =12² = (4×3)²=(2²×3)²

144=2^4 ×3²

so : xy = 2^4 ×3²

if  x and y the integere numbers so x and y are the divisors of 144

1  , 144,  2 ,72 , 4 , 36 , 8  18 , 3 , 48  , 6  , 24 , 9 , 16 , 12

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

relating to or denoting a system of numbers and arithmetic based on the number ten, tenth parts, and powers of ten.

it alot will look like this 4.4