● The short and long hands of a clock are 4 cm and 6 cm long respectively. Find the sum of distance travelled by their tips in 2 days. Class - 10th

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Step by step explanation please ​

Step-by-step explanation:

In 2 days, the short hand will complete 4 rounds.

∴ Distance moved by its tip 4(circumference of a circle of radius 4 cm)

=> 4×(2×22/7×4) cm

In 2 days, the long hand will complete 48 rounds.

∴ Distance moved by its tip 48(circumference of a circle of radius 6 cm)

=> 48×(2×22/7×6)cm = 12.672cm

Hence,

sum of distances moved by the tips of two hands of the clock

=> (704/7+12672)cm = 1910.85cm

┑(￣^￣)┍

30

step-by-step explanation:

times by times

the 8 in 8,420 is in the thousands place so it's value is 8 thousand.

the 8 in 6,870 is in the hundreds place so it's value is 8 hundred.

divide 8000 by 800 to find the answer:

8000 / 800 = 10

the 8 in 8,420 is 10 times greater than the 8 in 6,870