Write the equation of the circle with diameter endpoints of (-6, 3) and (-14, 13). (x−4)2+(y+5)2=164open paren x minus 4 close paren squared plus open paren y plus 5 close paren squared is equal to 164

(x−10)2+(y+8)2=164open paren x minus 10 close paren squared plus open paren y plus 8 close paren squared is equal to 164

(x−10)2+(y+8)2=41open paren x minus 10 close paren squared plus open paren y plus 8 close paren squared is equal to 41

(x−4)2+(y+5)2=41open paren x minus 4 close paren squared plus open paren y plus 5 close paren squared is equal to 41

(x+10)2+(y−8)2=164open paren x plus 10 close paren squared plus open paren y minus 8 close paren squared is equal to 164

(x+10)2+(y−8)2=41