Consider event A and event B. What is the probability that event Boccurs, given that event A has already occurred? ОА.
PBNA)
PA). PB)
OB. PIB A)
P(A)
OC. PCBN A)
PB)
OD. PBUA)
PCB)

amount of oatypop that contains the prize = 40%

amount   of oatypop which doesn't contain the prize = (100-40)=60%

probability that hannah will win a prize

    = s +f s +f f s+ff   f s+ff f f s+ infinity.where f= failure,s= success

=   or 60%

probability that hannah only has to buy 3 or less boxes before getting a prize= (s) and ( f s) and (ff s) and (f f f s)

        = = 87.04 %  

step-by-step explanation:

im pretty sure its

(8,15)

step-by-step explanation:

1/3 + 1/3 ≠ 2/6 because 1/3 alone = 2/6  

step by step explanation:

1/3 + 1/3 = 2/3       2/3=4/6

he kicked it up? is this the answer ?

step-by-step explanation: