If the coordinate of A is (0,-2) and the coordinate of B is (10,-6), then the midpoint of AB is ().

5, -4

Step-by-step explanation:

midpoint = x1 + x2/2 ,y1 + y2/2

= 0 + 10 /2 , -2 + -6/2

= 10/2 , -8/2

midpoint = 5, -4

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)