Mathematics, 07.04.2021 20:20 ginadesor3461
1. Find the equation of the parabola satisfying the given conditions.
Focus: (3,6); Directrix: x=β1
A. (xβ1)2=8(yβ6)
B. (yβ6)2=8(xβ1)
C. (xβ1)2=β8(yβ6)
D. (yβ6)2=β8(xβ1)
2. Find the equation of the parabola satisfying the given conditions.
Focus: (β6,3); Directrix: y=1
A. (yβ2)2=4(x+6)
B. (x+6)2=4(yβ2)
C. (x+6)2=β4(yβ2)
D. (yβ2)2=β4(x+6)
3. Find the equation of an ellipse that has foci at (β1,0) and (4,0), where the sum of the distances between each point on the ellipse and the two foci is 9.
A. (x+1)2+y2ββββββββββββ+(xβ4)2+y2ββββ ββββββββ=9
B. (xβ1)2+y2ββββββββββββ+(x+4)2+y2ββββ ββββββββ=9
C. (x+1)2+y2ββββββββββββ+(xβ4)2+y2ββββ ββββββββ=81
D. (xβ1)2+y2ββββββββββββ+(x+4)2+y2ββββ ββββββββ=81
4. Find the equation of a hyperbola that has foci at (β1,0) and (4,0), where the difference of the distances between each point on the ellipse and the two foci is 5.
A. (x+1)2+y2βββββββββββββ(xβ4)2+y2ββββ ββββββββ=25
B. (xβ1)2+y2βββββββββββββ(x+4)2+y2ββββ ββββββββ=5
C. (xβ1)2+y2βββββββββββββ(x+4)2+y2ββββ ββββββββ=25
D. (x+1)2+y2βββββββββββββ(xβ4)2+y2ββββ ββββββββ=5
Answers: 2
Mathematics, 21.06.2019 21:00
The sum of the first eight terms of an arithmetic progression is 9m + 14. the fifth term of the06 progression is 2m - 6, where m is a constant.given that the first term of the progression is 26,find the value of the common difference, d and thevalue of m.
Answers: 1
Mathematics, 21.06.2019 21:10
For each sentence below, find the value of x that makes each sentence true. (515) 5 = 25* x= (813)2 = 4* x=
Answers: 2
Mathematics, 22.06.2019 00:20
Maria solved an equation as shown below. what is the solution to mariaβs equation?
Answers: 1
1. Find the equation of the parabola satisfying the given conditions.
Focus: (3,6); Directrix: x=β1...
Biology, 13.10.2020 20:01
Mathematics, 13.10.2020 20:01
Mathematics, 13.10.2020 20:01
Mathematics, 13.10.2020 20:01
Biology, 13.10.2020 20:01
Mathematics, 13.10.2020 20:01
Mathematics, 13.10.2020 20:01
Mathematics, 13.10.2020 20:01
Mathematics, 13.10.2020 20:01