solve graphically this linear system of equations

The solution is the point (3, -1)

Step-by-step explanation:

We have the system of equations:

x = 3

y + 1 = 0

To solve this graphically, we need to graph these two lines and see in which point the lines intersect.

To graph the line x = 3, we need to draw a vertical line that passes through x = 3.

To graph y + 1 = 0

First we should isolate y.

y = -1

This is graphed as a horizontal line that passes through y = -1

The graph of these two lines can be seen in the image below.

Where the green line is x = 3, and the blue line is y = -1

Now, looking at the graph we can see that the lines do intersect in the point (3, -1)

Then the solution of the system is the point (3, -1)

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

898.1666667

step-by-step explanation:

5389/6 = 898.1666667