Given the f(x) = 3x2 + 21x – 54. What are the zeros of f(x)?
A. -3 and 18
B. -9 and 2
C. -6 and – 9
D. -6 and 2

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

explanation:

step-by-step explanation:

i believe the answer is y=0.25x+-3