The width of a rectangle is 4 feet and the diagonal length of he rectangle is 13 feet what is the measurement is the closest to the length of the rectangle in feet

The length is APPROXIMATELY equal to 12.4.

Step-by-step explanation:

Use the converse of the Pythagorean Theorem (+= [where "c" is both the longest side and the hypotenuse]) since a rectangle's diagonals will always cut it into two right triangles:

169-16=153.

≈ 12

or

or if the problem has to be exact (using radicals)

3*

I hope this helps ;)

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3