Please help solve this quadratic equation -9y²+12y-3=0​

-y = 0.66 ±

Step-by-step explanation:

Since the x-term coefficient is -9, we divide everything else by 9.

-y^2 + 1.33 - 0.33 = 0

Move the 0.33 to the right hand side of the equation.

-y^2 + 1.33 = -0.33

Take the 1.33, divide it by two, square it, and add it to both sides of the equation.

y^2 + 1.33 + 0.44 = -0.33 + 0.44

Complete the right side of the equation.

-y^2 + 1.33 + 0.44 = 0.11

Take 0.44, and subtract it by 0.11. In other words, move 0.44 to the right hand side of the equation.

-y^2 + 1.33 = 0.33

Take the square roots of both sides and solve.

=

-y + 0.66 =

-y = 0.66 ±

Really, really hope this helps!!

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step-by-step explanation:

step-by-step explanation:

rectangles are made up of 4 right angles, which means that a side and a base meet perpendicular to one another.   their slopes then have to reflect perpendicular slopes.   perpendicular slopes are opposite reciprocals of one another.   for example, if the slope of one line is +2/3, then the perpendicular slope to that would be -3/2.   so we look for that combination in our choices.

all of them satisfy that condition (so what's the question, i guess? )