Consider the probability that fewer than 46 out of 134 students will not pass their college placement exams. Assume the probability that a given student will not pass their college placement exam is 98%. Specify whether the normal curve can be used as an approximation to the binomial probability by verifying the necessary conditions. a. Yes
b. No

b. No

Step-by-step explanation:

Binomial approximation to the normal:

Binomial distribution has n trials, with p probability.

If

and , it can be approximated to the normal distribution.

Assume the probability that a given student will not pass their college placement exam is 98%.

This means that

134 students:

This means that

Necessary conditions:

Since the necessary condition n(1-p) < 10 is not satisfied, the answer is No, given by option b.

19.

step-by-step explanation:

you add the 9 in the tens column since it is a single digit and 9 plus zero is 9 so it is 19

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!