2. The prevalence of a trait is 76.8%. In a simple random sample of n = 50, how many individuals are expected to exhibit this characteristic and what is the corresponding standard deviation of this estimate?

It would be 18 cm

Hope i can you!

The question is kind of confusing. if it's asking how many variations of answers can you give. then do 4^5 for your answer.this would be something like the first question could be a and the 2nd c or first b next c etc. if you can, ask the teacher for a better confirmation of what it's asking. if i'm assuming correctly what it's asking, it's 625 different variations.