Among the contestants in a competition are 50 women and 26 men. If 5 winners are randomly selected, qhat js the probability that they are all men?

Probability that all winner are men = 0.0035 (Approx.)

Step-by-step explanation:

Given:

Number of women = 50

Number of men = 26

Total number winner = 5

Find:

Probability that all winner are men

Computation:

Total competitor = 50 + 26 = 76

Probability that all winner are men = 26/76 x 25/75 x 24/74 x 23/73 x 22/72

Probability that all winner are men = 7,893,600 / 2,216,980,800

Probability that all winner are men = 0.0035 (Approx.)

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

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step-by-step explanation:

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