Give reason why n2=x

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Step-by-step explanation:

1. Angles P₂ and N₁ are opposite angles of inscribed quadrilateral PMNQ, so are supplementary. Angles N₁ and N₂ form a linear pair, so are supplementary. Angles supplementary to the same angle (N₁) are congruent, hence P₂ = x ≅ N₂

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2. ΔPMQ is isosceles, so angle Q₁ is also congruent to x.

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3. In ΔPMQ, the sum of angles is 180°, so ...

  M₁ +2x = 180°

Dividing by 2 gives ...

  M₁/2 +x = 90°

Angle M₁ subtends arc PQ of circle M. Angle R inscribed in circle M subtends the same arc, so ...

  R = (M₁/2)

  R = 90° -x

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4. From the above, we know that angles N₂ and R are complementary (total 90°), so angle S₂ = 90°. Segment MS will only intersect chord PR at right angles at the midpoint of that chord.

Hence S is the midpoint of PR and PS = SR.

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

where r the answers

step-by-step explanation: