A bag of color tiles contains 2 red, 1 blue, 1 green, and 4 yellow. Sean reaches in and draws one tile without replacing it. He then draws a second tile and a third tile without replacing them. Which
of the following combinations is a possible draw?
F:red, blue, blue G:red, green, green H:yellow, blue, green J:blue, blue, green

H

Step-by-step explanation:

Since there is 4 yellows, 1 green, and 1 blue, there is no way you could draw 2 blues or 2 greens. Therefore, F, G, and J are immediately eliminated. The only answer left is H, and it makes sense. H is the answer.

H: yellow, blue, green

Step-by-step explanation:

F: red, blue, blue = cannot be true as there is 1 blue tile in bag and it cannot be drawn twice without replacing first draw.

G: red, green, green = cannot be true because 1 original green tile in bag cannot be drawn twice

J: blue,blue, green = cannot be true for same reason; 1 original blue tile cannot be drawn twice without replacement.

im a goose

step-by-step explanation:

gg5

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50