The average life of a brand of automobile tires is 30,000 miles, with a standard deviation of 2,000 miles. if a tire is selected and tested, find the probability that it will have a lifetime between 25,000 and 31,000 miles. assume the variable is normally distributed. give your answer rounded to four decimal places (to the nearest ten-thousandth).

Find the z scores for 25000 and 28000.

z1=( x – average)/ standard deviation =( 25000-30000)/ 2000 = -2.5

z2=( x – average)/ standard deviation =( 31000-30000)/ 2000 = 0.5

Find the corresponding P(z).

P (z1) = 0.00621

P (z2) = 0.15866

Subtract the probabilities to find the probability for the range,

(25000<= x <=28000)

P(x) = 0.15866-0.00621 = 0.1524

62.5 paisa

step-by-step explanation:

4000*70 = 280000

280000-(2000*90) = 100000

4000-2400 = 1600

100000/1600 = 62.5

( give brainliest)

i believe the correct answer is option 4.principalities were small territories that were run by russian rulers.

which statement correctly defines principalities in northern asia in the 1200s? principalities were small territories that were run by russian rulers.

hope i could ! : )