Which statement about k(x)=-x2-2x+15 is true? A The zeros are -3 and 5, because k(x)= -(x + 3)(x - 5).
B The zeros are -5 and 3, because k(x)= -(x + 5)(x - 3).
C The zeros are -5 and -3, because k(x)= -(x + 5)(x + 3).
D The zeros are 3 and 5, because k(x)= -(x - 3)(x - 5).​

The zeros are -5 and 3, because k(x)= -(x + 5)(x - 3).

Step-by-step explanation:

The function k(x)=-x2-2x+15 can be re-written as k(x) = -x^2 - 2x + 15, which in turn becomes -(x^2 + 2x - 15) after the negative sign is factored out.

The quantity inside parentheses is equivalent to (x + 5)(x - 3).  Setting this equal to zero, we get (x + 5) = 0 and (x - 3) = 0, so the zeros are {-5, 3}.  

Thus, Answer B is correct:  

The zeros are -5 and 3, because k(x)= -(x + 5)(x - 3).

The zeros are -5 and 3, because k(x)= -(x + 5)(x - 3).

Step-by-step explanation:

The quantity inside parentheses is equivalent to (x + 5)(x - 3).  Setting this equal to zero, we get (x + 5) = 0 and (x - 3) = 0, so the zeros are {-5, 3}.  

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.