What is 64x6+27 written as a sum of cubes?​

To transform the given expression to the sum of cubes, calculate first the cube root of the terms. The cube root of the first term, 64x^6 is 4x^2 and that of the second term, 27 is 3.

Thus, the answer to this is (4x^2)^3 + 3^3

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

12.4, 12.387, 12.26, 12.252, 6.241, 6.2, 6.015, 6.009, 1.411, 1.2, 1.056, 1.007, 0.31,   0.13, 0.5, 0.04

step-by-step explanation:

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