If f (-8)= 0 and f (x)= x^3-x^2-58x+112, find all the zeros of f(x) write your answer in ascending order

The zeros in ascending order are 2, 7, 8.

Step-by-step explanation:

Since f(-8) = 0, it means that (x + 8) is a factor of the function f(x)= x³ - x² - 58x + 112.

I have attached the long division of this to get the remaining factors of the polynomial function.

The remaining factor is;

x² - 9x + 14

Using quadratic formula via a calculator, we have; x = 7 and x = 2

Thus,the zeros of the polynomial function f(x)= x³ - x² - 58x + 112 in ascending order are;

2, 7, 8

answer: this is not a question

step-by-step explanation: this is a answer

the radius is 2 times the diameter.

step-by-step explanation: