At a museum cafe you can get a pre-made boxed lunch with a sandwich, fruit, and drink for only . The sandwiches are made with either turkey or ham.
The fruit is either an apple or an orange.
The drink is either bottled water or juice.
The number of boxes they make for every possible combination is the same. If you randomly choose one of the boxed lunches without knowing the contents, what is the probability you will get a turkey sandwich, an apple, and a bottle of water in your box?

1/5

step-by-step explanation:

the dice has 6 sides and there is only one 5 in a dice.

the answer for this question is 38

amount of oatypop that contains the prize = 40%

amount   of oatypop which doesn't contain the prize = (100-40)=60%

probability that hannah will win a prize

    = s +f s +f f s+ff   f s+ff f f s+ infinity.where f= failure,s= success

=   or 60%

probability that hannah only has to buy 3 or less boxes before getting a prize= (s) and ( f s) and (ff s) and (f f f s)

        = = 87.04 %  

step-by-step explanation:

any options?

step-by-step explanation: