A study of U. S. births published on the website Medscape from WebMD reported that the average birth weight of babies was 7.5 pounds and the standard deviation was about 1.2 pounds. Assume the distribution is approximately normal. Find the proportion of babies with birth weights of 6 pounds or less. Round your answer to 2 decimal places.

The proportion of babies with birth weights of 6 pounds or less is 0.1056 = 10.56%.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean and standard deviation , the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Average birth weight of babies was 7.5 pounds and the standard deviation was about 1.2 pounds.

This means that

Find the proportion of babies with birth weights of 6 pounds or less.

This is the pvalue of Z when X = 6. So

has a pvalue of 0.1056

The proportion of babies with birth weights of 6 pounds or less is 0.1056 = 10.56%.

(0.2)+(-8)=0.3+-3+0.3m is the equation i guess? ?

step-by-step explanation:

a.) list the factors of 40.

1/2/4/5/8/10/20/40

b.) list the factors of 40 that represent the number of cans that could be on each shelf.

5

c.) how many different arrangements of cans are possible?

just one because if you put more on one shelf you will go way over 40 and the cabinet will probably break.

d.) what are the possible arrangements of the cans?

put 5 cans on each self to reach 40 cans in total.

e.) which arrangement uses all the shelves?

5 because you can put 5 cans on each shelf, and since there are 8 shelfs you are equally going to get 40 cans.