Use the quadratic formula to determine the exact solutions to the equation. 2x2−5x+1=0

x=
or x=

x= 2.28

or, x= 0.219

Step-by-step explanation:

2x²-5x+1 =0

a= 2, b= -5 and c= 1

x= (-b + √(b²-4ac))/2a

= (5 + √(25-8))/4

= (5 + √17)/4

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

answer: -0.5 would be the most likley outcome

step-by-step explanation: