Write the equation of the line which passes through (1, 2) and with slope of −1/3 in standard form.

Step-by-step explanation:

The equation of a line which passes through (x₁, y₁) and with slope of m in point-slope form:

                                y - y₁ = m(x - x₁)

m = -¹/₃

(1, 2)    ⇒   x₁ = 1,  y₁ = 2

Therefore,  the equation of the line which passes through (1, 2) and with slope of −1/3 in point-slope form:

y - 2 = -¹/₃(x - 1)

y - 2 = -¹/₃x + ¹/₃                     {add ¹/₃x to both sides}

¹/₃x + y - 2 = ¹/₃                     {add 2 to both sides}

¹/₃x + y = 2¹/₃                       {multiply both sides by 3}

x + 3y = 7            

3030 ur welcome

step-by-step explanation:

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!