Factor completely: 2x3 + 10x2 + 4x + 20

prime

(2x + 10)(x2 + 2)

2[(x + 5)(x2 + 2)]

(x + 5)(2x2 + 4)

B) 2[(x + 5)(x2 + 2)]

Step-by-step explanation:

Given: 2x^3 + 10x^2 + 4x + 20

Here 2 is a common factor, so we take it out and write the remaining terms in the parenthesis.

2(x^3 + 5x^2 + 2x + 10)

Now let's take (X^3 + 5x^2 +2x + 10), we group and factor them as follows:

(x^3 + 5x^2 + 2x + 10) = x^2(x+5) + 2(x + 5) = (x+5)(x^2 +2)

When we combine them, we get

2x^3 + 10x^2 + 4x + 20 = 2(x+5)(x^2 +2)

Therefore, the answer is B) 2[(x + 5)(x2 + 2)]

Hope this will helpful.

Thank you.

false

step-by-step explanation:

false : it can not go to 9 the highest that part can go is 7

here is your proof