The bear population in canada was 380,000 in the year 2015, and environmentalists think that the population is increasing at a rate of 2.5% per year

The bear population after t years will be:

p(t) = 380,000*(1 + 0.025)^t

Step-by-step explanation:

Here the question is missing, so i will found an equation that can tell us the bear population as a function of the number of years that have passed since 2015, represented with the variable t.

The initial bear population in Canada was 380,000.

Each year the population increases by a 2.5%

Then after one year, the population is:

p(1) = 380,000 + 380,000*(2.5%/100%)

p(1) = 380,000 + 380,000*(0.025) = 380,000*(1 + 0.025)

After another year the population increases by 2.5% again, then the new population will be:

p(2) = 380,000*(1 + 0.025) +  380,000*(1 + 0.025)*(2.5%/100%)

p(2) =  380,000*(1 + 0.025) +  380,000*(1 + 0.025)*(0.025)

p(2) = 380,000*(1 + 0.025)*(1 + 0.025)

p(2) = 380,000*(1 + 0.025)^2

So we already can see the pattern here, the bear population after t years will be:

p(t) = 380,000*(1 + 0.025)^t

step-by-step explanation: h: (- 3, 6)

m: (1, - 2)

o: (7, 6)

r: (- 9, - 2)

midpoint of hm: (- 1, 2)

midpoint of or: (- 1, 2)

therefore, b is the midpoint of both diagonals bisect each other !

to prove the diagonals are perpendicular, show that the product of the slopes = - 1

circle area = pi * radius^2

if diameter = 10 then radius = 5

circle area = pi * 5^2

circle area = pi * 25

circle area = 78.5398163397 square units

step-by-step explanation: