What are the zeros of f(x) = x2 + x – 30? A. x = –6 and x = 5
B. x = –5 and x = 6
C. x = –15 and x = 2
D. x = –2 and x = 15

Answer A is correct.  (x + 6)(x - 5) = x^2 + x - 30.

Step-by-step explanation:

Note that -30 = (-5)(6) and (5)(-6). This quadratic can be factored easily:

x^2 + x - 30 = (x + 6)(x - 5) is correct because 6x - 5x = x, the middle term of x^2 + x - 30.

Setting each factor equal to zero, one by one, we get:

x + 6 = 0 => x = -6, and x - 5 = 0 => x = 5

Answer A is correct.

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.

15.36 per mile

but forgot to round

i am pretty sure