What is the area of a triangle whose vertices are r(−4,2) r ( − 4 , 2 ) , s(1,2) s ( 1 , 2 ) , and t(−5,−4)

The area of that triangle would be 5 units².
The formula for the area of a triangle is 1/2bh; with b being base and h being the height.
The base of the triangle is length of segment TS which is 5 units
The height of the triangle is 4-2= 2 units.
5×2=10
10÷2= 5

I’m going to infer you said parallel.solve for yy= -1/2x+7/4lines that are parallel have the same slope, different y intercept.so we know m is -1/2then from there solve for y intercept.

C, e, and a (hope it )