Find the surface area of the right triangular prism (above) using its net (below).

144 units²

Step-by-step explanation:

The net of the right triangular prism consists of 3 rectangles and 2 equal triangles

Let's solve for the area of each:

✔️Area of rectangle 1 = L*W

L = 11

W = 3

Area of rectangle 1 = 11*3 = 33 units²

✔️Area of rectangle 2 = L*W

L = 11

W = 4

Area of rectangle 2 = 11*4 = 44 units²

✔️Area of rectangle 3 = L*W

L = 11

W = 5

Area of rectangle 3 = 11*5 = 55 units²

✔️Area of the two triangles = 2(½*base*height)

base = 4

height = 3

Area of the two traingles = 2(½*4*3)

= 12 units²

✔️Surface area of the right triangle = area of rectangle 1 + area of rectangle 2 + area of rectangle 3 + area of the two triangles

= 33 + 44 + 55 + 12

= 144 units²

50*10 is greater

step-by-step explanation:

if you add the zero from 10 to 50, it will give you a bigger number.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3