In the year 2005, a total of 750 fish were introduced into a manmade lake. the fish population was expected to grow at a rate of 8.3% each year.

what will the fish population be in 2050?

round to the nearest whole number.

enter your answer in the box.

The population of the fish is given by P(t) = 750(1 + 0.083)^t; where t is the number of years after 2005.
Here, t = 2050 - 2005 = 45

Population in 2050 = 750(1.083)^45 = 750(36.16) = 27,123

both graphs increase on their domain

neither graph has a y-intercept

step-by-step explanation:

the following points can be visualized easily from the graph

there is a hike in both the graphs so the graphs are increasing on their domain.x-intercept of log x and log 6x are differentthere is a vertical asymptote of both the graphs so there is no y-interceptas both the graphs are increasing so there is no horizontal asymptote