The U. S. Postal Service is to deliver a letter to a certain postal ZIP 4 code. Find the probability that the ZIP 4 code is correct if the sender (a) randomly chooses the code, (b) knows the five-digit code but must randomly choose the last four digits, and (c) knows the five-digit code and the first two digits of the plus 4 code.

StateCityZIP Code(s)

Arizona (AZ)Phoenix85001 thru 85055

Arkansas (AR)Little Rock72201 thru 72217

California (CA)Sacramento Los Angeles Beverly Hills94203 thru 94209 90001 thru 90089 90209 thru 90213

Colorado (CO)Denver80201 thru 80239

Step-by-step explanation:

Hope This Helps

let's cover over the formula of the vertex:

y = a(x – h)^2 + k

in this formula, (h,k) are the vertex, always remember that the positive or negative value of the vertex is based on the sign it has.

for example, if the vertex is -3,-6 then both the x and y value would have the positive sign attached to it and if it were a positive x and y value, then a negative sign would be attached to it.

with that being said, for our problem the x value is a positive one so we are looking for a number with a negative sign next to it, in this case the first and second choice.

however, for the first answer choice it isn't quite part of the formula so we know that the answer choice correctly displays the x value.

to confirm, we can see if the -1 fits correctly with the second answer choice, and as mentioned above a negative number will have a positive sign attached to it. so, for our problem we can see that -1 has been changed to +1, so we can confirm that the second answer choice is correct.

hence, our final answer is y=(x - 1)^2 + 1

the awnser is visionary