This graph shows two lines, A and B based on the graph which statement is correct about the solution to the system of equations for lines A and B

(4,4) is the solution to line A but not to line B.
(4,4) is the solution to both lines A and B.
(5,1) is the solution to line B but not to line A
(0,2) is the solution to both lines A and B

01101000 01110100 01110100 01110000 01110011 00111010 00101111 00101111 01110111 01110111 01110111 00101110 01111001 01101111 01110101 01110100 01110101 01100010 01100101 00101110 01100011 01101111 01101101 00101111 01110111 01100001 01110100 01100011 01101000 00111111 01110110 00111101 01100100 01010001 01110111 00110100 01110111 00111001 01010111 01100111 01011000 01100011 01010001

Step-by-step explanation:

the second one

Step-by-step explanation:

step-by-step explanation:

a rhombus is a parallelogram enjoying his symmetry.

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3