Find the area and perimeter of a rectangle that has a length of (x + 24) and (x + 16). Show all work for full credit.

Perimeter of rectangle = 4x + 80

Area = x² + 40x + 384

Step-by-step explanation:

Perimeter of rectangle = 2*(length + width)

                                      = 2* (x + 24 + x + 16)

                                      = 2*( x +x + 24 + 16)    {Combine like terms}

                                      = 2* (2x + 40)

Use Distributive property : a*(b +c) = a *b + a*c

                                     = 2*2x + 2*40

                                     = 4x + 80

Area of rectangle = length * width

                             = (x + 24) (x + 16) {use FOIL method}

                            = x*x + x*16 + 24*x + 24*16

                             = x² + 16x + 24x + 384  {Combine like terms}

                             = x² + 40x + 384

there would only be 50 odd numbers between 1 and 100 so therefor there would be 50 even so that would only be 50 odd numbers.