The length of a rectangle is 2 inches less than three times its width. If the perimeter of the rectangle is 108 inches, find its length and width.

the length is 40 inches

the width is 14 inches

Step-by-step explanation:

We start by representation with variables

let l be the length and w the width

Length l is 2 inches less than 3 times width (3w)

l = 3w-2 ••••(i)

Mathematically,

we have the perimeter calculated as follows;

P = 2(l + w)

2(l + w) = 108

l + w = 108/2

l + w = 54 ••••••(ii)

Substitute equation i into ii

3w-2 + w = 54

4w = 54 + 2

4w = 56

w = 56/4

w = 14

Recall;

l + w = 54

14 + l = 54

l = 54-14

l = 40 inches

  21.3

step-by-step explanation:

multiplying the given equation by c/sin(25°), we get

  c = 9/sin(25°) ≈ 21.2958 ≈ 21.3

we assume "c" is the length of ab, the side opposite angle c in triangle abc.

d

step-by-step explanation: