A bag contains 42 red, 45 green, 20 yellow, and 32 purple candies. You
pick one candy at random. Find the
probability that it is green or yellow.

65/139 fraction form

0.47 decimal form

Step-by-step explanation:

Total sample space , n (s) = 139

no of green candies , n (g) = 45

no. of yellow candies , n (y) = 20

Probability that is green or yellow is

P( g or y) = P(g) + P(y)

               = n(g) / n(s) + n (y) / n(s)

               = 45 / 139 + 20 / 139

               = 65 / 139

hope it will help :)

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

step-by-step explanation:

mean or average is 40.6