Using L Hospital's rule, evaluate :
lim
x →0(x² – Sin²x)/x^2​

0

Step-by-step explanation:

L Hospital's rule states that as long as u have the form

of infinity / infinity or 0/0 in general you can take its derivative to find the limit.

In this case as X tends to 0, the numerator tends to 0

Denominator will also tends to 0.

We have the 0 / 0 form, which means we can take the derivative for its numerator and denominator which gives

(2x - 2SinxCosx) / 2x | lim x -> 0

= (2x - Sin2x) / 2x | lim x -> 0

Based on this equation, as x tends to 0

both numerator and denominator tends to 0.

So we take its second derivative,

(2 - 2Cos2x) / 2

Now as x -> 0,

we will get (2 - 2)/2 = 0

all but the second one

step-by-step explanation:

cuz that one goes over 180

mark brainliest

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47